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(7)^2-4x(6x-10)=0
We add all the numbers together, and all the variables
-4x(6x-10)+49=0
We multiply parentheses
-24x^2+40x+49=0
a = -24; b = 40; c = +49;
Δ = b2-4ac
Δ = 402-4·(-24)·49
Δ = 6304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6304}=\sqrt{16*394}=\sqrt{16}*\sqrt{394}=4\sqrt{394}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-4\sqrt{394}}{2*-24}=\frac{-40-4\sqrt{394}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+4\sqrt{394}}{2*-24}=\frac{-40+4\sqrt{394}}{-48} $
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